Microwave Engineering Final Exam Solutions

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PIN = abcd = 3194, a = 3, b = 1, c = 9, d = 4

 

Total points = 120

 

1. C1 = 10a (nF), L1 = 100b (pH), R1 = c/1000 (¥Ø), R2 = 10d (G¥Ø). Neglect R2 and R1. Find the self-resonant frequency fr (Hz). (10 points)

(Answer) 10 points

C1 = 10a = 30 nF, L1 = 100b = 100 pH

fr = 1/[2¥ð(L1C1)1/2] = 1/[2¥ð(100¡¿10−12¡¿30¡¿10−9)1/2] = 1/[2¥ð(3¡¿10−18)1/2] = 109/[2¡¿31/2¥ð] = 91.9 MHz

 

2. Parallel-plate capacitor

Plate area: S = a cm2

Plate separation: d = b/10 cm

f = 10 MHz

Real part of the complex permittivity filling the capacitor: ¥å' = c¥å0

Imaginary part: ¥å'' = d/100 ¥å'

Find 1) the value of C and 2) the value of R. (20 points)

(Answer)

S = a cm2 = 3 cm2 = 3¡¿10−4 m2 , d = b/10 cm = 0.1 cm = 0.001 m

¥å' = c¥å0 = 9¥å0, ¥å'' = d/100 ¥å' = 0.04(9¥å0) = 0.36¥å0

 

1) (10 points)

C = ¥å' S / d = 9¡¿(8.854¡¿10−12)¡¿( 3¡¿10−4)/0.001 = 23.9 pF

 

2) (10 points)

R = d/[(¥ø¥å'')S] = 0.001/[2¥ð(10¡¿106)¡¿(0.36¡¿8.854¡¿10−12)¡¿ (3¡¿10−4)] = 16.6 k¥Ø

 

3. Find 1) the conductor loss power density pc (W/m3), 2) the dielectric loss power density pd (W/m3), and 3) the dielectric stored power density pe (W/m3) in a medium with

¥å' = d¥å0, ¥å'' = (c/100)¥å', ¥ò = (b/100) (S/m) , | E | = 10a V/m, f = 100a MHz (30 points)

(Answer)

¥ø = 2¥ðf = 2¥ð(100a¡¿106) = 600¥ð¡¿106 Hz

| E | = 10a = 30 V/m

¥ò = b/100 = 0.01 (S/m)

¥å' = d¥å0 = 4¥å0

¥å'' = (c/100)¥å' = 0.009(4¥å0) = 0.036¥å0

 

1) (10 points)

pc = (1/2)¥ò| E |2 = 0.5¡¿0.01¡¿302 = 4.50 (W/m3)

 

2) (10 points)

pd = (1/2)¥ø¥å''| E |2 = 0.5¡¿(600¥ð¡¿106)¡¿(0.036¡¿8.854¡¿10−12)¡¿302 = 0.270 (W/m3)

 

3) (10 points)

pe = (1/2)¥ø¥å'| E |2 = 0.5¡¿(600¥ð¡¿106)¡¿(4¡¿8.854¡¿10−12)¡¿302 = 30.0 (W/m3)

 

4. Planewave

¥å = d¥å0, ¥ì = a¥ì0, f = 100b MHz

Find 1) the intrinsic impedance ¥ç, 2) the propagation constant k, and 3) the wavelength ¥ë. (30 points)

(Answer)

¥å = d¥å0 = 4¥å0, ¥ì = a¥ì0 = 3¥ì0, f = 100b = 100 MHz

 

1) (10 points)

¥ç = (¥ì/¥å)1/2 = (3/4)1/2 (¥ì0/¥å0)1/2 =  (3/4)1/2¡¿377 = 326 ¥Ø

 

2) (10 points)

k = 2¥ðf (¥ì/¥å)1/2 = 2¥ðf (3¡¿4)1/2 (¥ì0¥å0)1/2 = 2¥ð¡¿100¡¿106¡¿ (3/4)1/2/(3¡¿108) = 0.181 rad/m

 

3) (10 points)

¥ë = 2¥ð/k = 2¥ð/0.181 = 34.7 m

 

5. Planewave reflection and transmission, normal incidence

¥å1 = b¥å0, ¥å2 = c¥å0, ¥ì1 = d¥ì0, ¥ì2 = a¥ì0

Find 1) the reflection coefficient ¥Ã and 2) the transmission coefficient ¥ó. (20 points)

(Answer)

¥å1 = b¥å0 = ¥å0, ¥å2 = c¥å0 = 9¥å0, ¥ì1 = d¥ì0 = 4¥ì0, ¥ì2 = a¥ì0 = 3¥ì0

¥ç2 = (¥ì2/¥å2)1/2 = (3/9)1/2 (¥ì0/¥å0)1/2 = (1/3)1/2¥ç0

¥ç1 = (¥ì1/¥å1)1/2 = (4/1)1/2 (¥ì0/¥å0)1/2 = 2¥ç0

 

1) (10 points)

¥Ã = (¥ç2¥ç1) / (¥ç2 + ¥ç1) = [(1/3)1/2 − 2] / [(1/3)1/2 + 2] = −0.55

 

2) (10 points)

¥ó = 2¥ç2 / (¥ç2 + ¥ç1) = 2(1/3)1/2 / [(1/3)1/2 + 2] = 0.45

 

6. Write a Python code for Problem 6. Submit your source code and the result of your program execution. (10 points)

(Answer)